3x^2+58x-1400=0

Solution for 3x^2+58x-1400=0 equation:

3x^2+58x-1400=0

a = 3; b = 58; c = -1400;
Δ = b2-4ac
Δ = 582-4·3·(-1400)
Δ = 20164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20164}=142$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-142}{2*3}=\frac{-200}{6}
=-33+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+142}{2*3}=\frac{84}{6}
=14
$